Question

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?​

Answer 1

Answer:

let father be = x

then son=x-29

grand father=x+26

∴x+x−29+x+26=135

3x−3=135

Transpose 3 to RHS, we will get,

3x=138

Divides both sides by 3, we will get

⇒x=46

Baichung's father age =x=46 years

Baichung's age =x−29=46−29=17 years

Baichung's grandfather's age =x+26=46+26=72 years

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Answer 2

Answer

• Baichung's age => 17 years.

• Baichung's father age => 46 years.

• Baichung's grandfather age => 72 years.

Given

• Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung.

• The sum of the ages = 135 years.

To Find

• Age of each of them.

Step By Step Explanation

Let us assume ⤵

Baichung’s age be x .

Baichung’s father age = x + 29

Baichung’s grandfather age = x + 29 + 26

By substituting the values

$\longmapsto \sf \: x + x + 29 + x + 29 + 26 = 135 \\ \\\longmapsto \sf3x + 84 = 135 \\ \\\longmapsto \sf 3x = 135 - 84 \\ \\ \longmapsto \sf3x = 51 \\ \\ \longmapsto \sf x = \cancel\cfrac{51}{3} \\ \\ \longmapsto \bf \: x = 17$

Therefore,

Baichung’s age = x => 17 years.

Baichung’s father age = x + 29 = 17 + 29 => 46 years.

Baichung’s grandfather age = x + 29 + 26 = 17 + 29 + 26 => 72 years.

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