Question

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung. the sum of the age of all the three is 135 years. what is the age of each one of them?
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Answer 1

Given :

• Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .
• The sum of the age of all the three is 135 years.

Solution :

$\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}$

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

$\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}$

$\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}$

A.T.Q :

$\longmapsto\tt{x+x-26+x-55=135}$

$\longmapsto\tt{3x-81=135}$

$\longmapsto\tt{3x=135+81}$

$\longmapsto\tt{3x=216}$

$\longmapsto\tt{x=\cancel\dfrac{216}{3}}$

$\longmapsto\tt\bf{x=72}$

Value of x is 72 .

Therefore :

$\longmapsto\tt{Age\:of\:his\:Grandfather=x}$

$\longmapsto\tt\bf{72\:yrs}$

$\longmapsto\tt{Age\:of\:his\:Father=72-26}$

$\longmapsto\tt\bf{46\:yrs}$

$\longmapsto\tt{Age\:of\:Baichung=72-55}$

$\longmapsto\tt\bf{17\:yrs}$

Answer 2

• Age of Baichung's grandfather = 72 years
• Age of Baichung's father = 46 years
• Age of Baichung = 17 years

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Explanation :

G I V E N :

• Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung.
• Sum of the ages of all the three is 135 years.

TO F I N D :

• Age of each one of them = ?

S O L U T I O N :

• Let age of Baichung's grandfather be m years.

Therefore,

• Age of Baichung's father = (m - 26) years
• Age of Baichung = m - 26 - 29 = (m - 55) years.

A/q,

✏ㅤㅤm + (m - 26) + (m - 55) = 135

✏ㅤㅤm + m - 26 + m - 55 = 135

✏ㅤㅤ2m + m - 55 - 26 = 135

✏ㅤㅤ3m - 81 = 135

✏ㅤㅤ3m = 135 + 81

✏ㅤㅤ3m = 216

✏ㅤㅤm = 216/3

✏ㅤㅤm = 72$\:$

✇ Finding there ages :-

✏ㅤㅤAge of Baichung's grandfather =ㅤㅤㅤㅤm = 72 years

✏ㅤㅤAge of Baichung's father = m - 26 ㅤㅤㅤ= 72 - 26 = 46 years

✏ㅤㅤAge of Baichung = m - 55 = 72 - ㅤㅤㅤㅤ55 = 17 years

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