Math, asked by manimalathi, 1 year ago

baichung's father is 26 years younger than baichung's grand father and 29 years older than baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answers

Answered by BRAINLYY
32
Let Baichung's father age be x

Then,
Age of Baichung = x - 29
Age of Baichung's Grandfather = x + 26

It is given that sum of their ages = 135

=> x + x - 29 + x + 26 = 135
=> 3x - 3 = 135
=> 3x = 138
=> x = 46

BAICHUNG'S FATHER AGE = 46
BAICHUNG'S AGE = 46 - 29 => 17
BAICHUNG'S GRANDFATHER'S AGE = 46 + 26 => 72

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MARK AS BRAINLIEST
Answered by tribeking22otbgm9
10
Assume: baichung = x
baichung's father = y
baichung's grandfather = z

y = z - 26
z = y + 26

y = x + 29
x = y - 29

x + y + z = 135
(y - 29) + y + (y + 26) = 135
3y - 3 = 135
3y = 135 + 3
3y = 138
y = 138 : 3
y = 46

z = y + 26
z = 46 + 26
z = 72

x = y - 29
x = 46 - 29
x = 17

Baichung age is 17 years old
Baichung's father age is 46 years old
Baichung's grand father age is 72 years old
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