Math, asked by aqibshaikh7715, 11 months ago

Baichung's father is 26 years younger than Baichung's grant father and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answers

Answered by Anonymous
8

Answer:

baichung's father age = 46 years

baichung's age  = 17 years

baichung's grandfather age  = 72 years

Step-by-step explanation:

let baichung's father age be = X

baichung's age = X-29

baichung's grandfather age = X+26

sum of all ages = 135

X+X-29+X+26=135

3X-3 = 135

3X = 135+3

3X = 138

X = 46

baichung's father age = 46 years

baichung's age = X-29 = 46-29 = 17 years

baichung's grandfather age = X+26 = 46+26 = 72 years


Anonymous: please mark brainliest
Answered by samikshasureshshetka
2

Answer: Let Baichung's father age be x

then baichung's grandfather is x+26years

baichung's present age is x-29years

sum of their age i 135 years

therefore x+[x+26]+[x-29]=135

x + x + x + 26 - 29 = 135

3x - 3 =135

3x = 135 - 3

3x = 138

x = 138/3 = 46

x =46

therefore baichung's father age is 46 years

x - 29 = 46 - 29 = 17 years is baichung's age

x + 26 = 46 + 29 = 72 years is baichung's father age

baichung's age = x years

baichung's father age = [x+29]years

baichung's grandfather age = [x +29]= x + 55 years

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