Question

baichung's father is 26 years younger than his grandfather and 29 years older to baichung. the sum of the ages of all three is 135 years.what is the age of each one of them?​

Answer 1

Answer:

Given :

Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .

The sum of the age of all the three is 135 years.

Solution :

$\longmapsto\tt{Let\:Age\:of\:Grandfather\:be=x}$

As Given that Baichung 's father is 26 years younger than Baichung's grandfather and 29 year older than Baichung .So ,

$\longmapsto\tt{Age\:of\:Baichung's\:Father=x-26}$

$\longmapsto\tt{Age\:of\:Baichung=x-26-29=x-55}$

A.T.Q :

$\longmapsto\tt{x+x-26+x-55=135}$

$\longmapsto\tt{3x-81=135}$

$\longmapsto\tt{3x=135+81}$

$\longmapsto\tt{3x=216}$

$\longmapsto\tt{x=\cancel\dfrac{216}{3}}$

$\longmapsto\tt\bf{x=72}$

Value of x is 72 .

Therefore :

$\longmapsto\tt{Age\:of\:his\:Grandfather=x}$

$\longmapsto\tt\bf{72\:yrs}$

$\longmapsto\tt{Age\:of\:his\:Father=72-26}$

$\longmapsto\tt\bf{46\:yrs}$

$\longmapsto\tt{Age\:of\:Baichung=72-55}$

$\longmapsto\tt\bf{17\:yrs}$

Answer 2

Let Baichung’s age be x years, then Baichung’s father’s age = (x+29)

years and Baichung’s granddaughter’s age =

(x+29+26)=(x+55) years.

⇒ 3x+84=135 ⇒3x+84−84=135−84

[Subtracting 84 from both sides]

⇒ 

$3x = 51 = \frac{3x}{3} = \frac{51}{3}$

[Dividing both sides by 3]

》》 x = 17 years.

●●●●●●●●●●●●●●●●●●

Hence, Baichung’s age = 17 years, Baichung’s father’s age = 17 + 29

= 46 years

And Baichung’s granddaughter’s age

= 17 + 29 + 26 = 72 years.

The sum of the ages of all the three is 135 years. What is the age of each one of them? years and Baichung's granddaughter's age = (x+29+26)=(x+55) years. x = 17 years.

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