Question

Baichung's father is26 years younger than Baichung's grandfather and 29 years older than Baichung . The sum of the age of the three is 135 yeats . What is the age of each one of them​

Answer 1

Answer:

let the age of Baichung be x years.

age of father would be x + 29 years.

age of grandfather would be x + 29 + 26

= x + 55 years

now sum of their ages is given to be 135 years.

so,

x + x + 29 + x + 55 = 135

3x + 84= 135

3x = 135 - 84

3x = 51

x = 51/3

x = 17

age of Baichung = 17 years

age of Baichung's father = 17 + 29 = 46 years

age of Baichung's grandfather = 17 + 55 = 72 years.

Answer 2

Let the age of Baichung’s father be x.

Then, the age of Baichung’s grandfather = (x+26)

and, Age of Baichung = (x-29)

According to the question,

→ x + (x+26) + (x-29) = 135

⇒ 3x + 26 – 29 = 135

⇒ 3x – 3 = 135

⇒ 3x = 135 + 3

⇒ 3x = 138

⇒ x = 138/3

⇒ x = 46

Age of Baichung’s father = x = 46

Age of Baichung’s grandfather = (x+26) = 46 + 26 = 72

Age of Baichung = (x-29) = 46 – 29 = 17