Question

Baichung's grandfather is 26 years older than baichung's father and baichung is 17 years younger the sum of their ages are​

Answer 1

Answer:

3x+9 years

Step-by-step explanation:

let baichung's fathers age be x years

Baichung's grandfather is x+26 years

Baichung is x-17 years

sum of their ages = x+26+x+x-17= (3x+9) years

Answer 2

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Let the age of Baichung’s father = m year

Since, Baichung’s father is 26 year younger than Baichung’s grand father

Therefore, Age of Baichung’s grandfather = Age of Baichung’s father + 26 = m + 26 year

Since, Baichung’s father is 29 year older than Baichung

Therefore, Age of Baichung = Age of Baichung’s father – 29 = m – 29 year

Now, we have

Age of Baichung = m – 29 year

Age of Baichung’s father = m year

Age of Bahichung’s grandfather = m + 26 year

According to question, the sum of ages of all the three = 135 year

Therefore,

Age of Baichung + Age of Baichung’s father + Age of Baichung’s grandfather = 135

⇒ (m – 29) + m + (m + 26) = 135 year

⇒ m – 29 + m + m + 26 = 135 year

⇒ m + m + m – 29 + 26 = 135 year

⇒ 3m – 3 = 135 year

After transposing – 3 to the RHS, we get

3m = 135 year + 3

⇒ 3m = 138 year

After dividing both sides by 3, we get

This means age of Baichung’s father = 46 year

Now, by substituting the value of m, we can calculate the age of Baichung and the age of Baichun’s grandfather.

Therefore,

Age of Baichung = m – 29 = 46 – 29 = 17 year

Age of Baichung’s grandfather = m + 26 = 46 + 26 = 72 year

Thus,

Age of Baichung = 17 year

Age of Baichung’s father = 46 year

Age of Baichung’s grandfather = 72 year