Question

baichungs father is 26 year's younger than baichungs grandfather and 29 years older than baichung the sum of the ages of all three is 135. years. What is the age of each one of them​

Answer 1

Step-by-step explanation:

baichung's age - x

baichung's father's age - x+29

baichung's grandfather's age - x+29+26 =

x+55

equation - x+x+29+x+55 = 135

3x+84 = 135

3x = 135-84

3x = 51

x = 51/3

x = 17

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baichung's age - 17 years

baichung's father's age - 17 + 29 = 46 years

baichung's grandfather's age - 17 + 29 + 26

= 72 years

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hope it helps.......✶✶✶✶

Answer 2

Let Father's age be x yrs

Grandfather's age is x+26 yrs

Therefore Baichungs age is x-29 yrs

According to the problem:

x+x-29+x+26= 135

=2x-29+x+26=135

=3x-29=135-26

=3x=109+29

=3x=138

=x=138/3

=x= 46

Father's age =46 yrs

Grandfather's age=x+26=46+26=72 yrs

Baichungs age= x-29=46-29=17 yrs

Hope this helps....

THANK YOU