baichungs father is 26 years younger than Baichung grandfather and 29 years older than baichungthe sum of the ages of all the three is 135 years what is the age of each one of them
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hey here is your answer..✌
let the age of baiichung be x years
then,age of baichung's father=(x+29) years
and,the age of baichung's grandfather=(x+29+26) years
=(x+55)years
then the sum of all ages is 135years
therefore,
x+(x+29)+(x+55)=135
3x+84=135
3x=135-84
3x=51
x=51/3
=17
so,x=17
age of baiichung is x=17
age of baichung's father is (x+26)=17+29
=46
age of baichung's grandfather is (x+55)=17+55
=72..
hope this answer helps you
plz mark it as brainlist answer
let the age of baiichung be x years
then,age of baichung's father=(x+29) years
and,the age of baichung's grandfather=(x+29+26) years
=(x+55)years
then the sum of all ages is 135years
therefore,
x+(x+29)+(x+55)=135
3x+84=135
3x=135-84
3x=51
x=51/3
=17
so,x=17
age of baiichung is x=17
age of baichung's father is (x+26)=17+29
=46
age of baichung's grandfather is (x+55)=17+55
=72..
hope this answer helps you
plz mark it as brainlist answer
truefriendship:
this is question from 8th std NCERT maths book
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1
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