Question

Baichungs father is 26 years younger than Baichungs grandfather and 29 years older than Baichung. The sum of each one of them

Answer 1

Answer:

Let age of Baichung's father age be x years

∴ Baichung's age and his grandfather's age ⇒(x−29) and (x+26) yrs respectively.

As per the question, Sum of ages of 3 people =135 years

∴x+x−29+x+26=135

3x−3=135

Transpose 3 to RHS, we will get,

3x=138

Divides both sides by 3, we will get

x=  

3

138

​  

 

⇒x=46

Baichung's father age =x=46 years

Baichung's age =x−29=46−29=17 years

Baichung's grandfather's age =x+26=46+26=72 years

Step-by-step explanation:

Answer 2

Answer:

ANSWER

Let age of Baichung's father age be x years

∴ Baichung's age and his grandfather's age ⇒(x−29) and (x+26) yrs respectively.

As per the question, Sum of ages of 3 people =135 years

∴x+x−29+x+26=135

3x−3=135

Transpose 3 to RHS, we will get,

3x=138

Divides both sides by 3, we will get

x=

3

138

⇒x=46

Baichung's father age =x=46 years

Baichung's age =x−29=46−29=17 years

Baichung's grandfather's age =x+26=46+26=72 years