Question

balajee walks 4 whole 3 upon 5 km in a day . how much distance will be cover in 5 whole 1 upon 2 days?​

Answer 1

Answer:

$\rm 20\dfrac{53}{10}$ km

Step-by-step explanation:

As per the provided information in the given question, we have :

• Balajee walks $\rm 4\dfrac{3}{5}$ km in 1 day.

We are asked to calculate how much distance will be cover in $\rm 5 \dfrac{1 }{2}$ days.

According to the question :

$\longmapsto \rm {Distance \; covered_{(1 \; day)} = 4\dfrac{3}{5} \; km }$

Converting mixed fraction in proper fraction.

$\longmapsto \rm {Distance \; covered_{(1 \; day)} = \dfrac{23}{5} \; km }$

∴ Distance covered in one day is 23/5 km.

Now, if in one day he covers 23/5 km. So,

$\longmapsto \rm {Distance \; covered_{(5\frac{1}{2} \; days)} = \Bigg (5 \dfrac{1 }{2} \times 4\dfrac{3}{5}\Bigg ) \; km }$

Converting mixed fraction in proper fraction.

$\longmapsto \rm {Distance \; covered_{(5\frac{1}{2} \; days)} = \Bigg ( \dfrac{11 }{2} \times \dfrac{23}{5}\Bigg ) \; km }$

Rearranging the terms.

$\longmapsto \rm {Distance \; covered_{(5\frac{1}{2} \; days)} = \Bigg ( \dfrac{11 \times 23}{2\times 5} \Bigg ) \; km }$

Performing multiplication in both the numerator and the denominator.

$\longmapsto \rm {Distance \; covered_{(5\frac{1}{2} \; days)} = \Bigg ( \dfrac{253}{10} \Bigg ) \; km }$

Now, convert the proper fraction in mixed fraction.

$\longmapsto \bf {Distance \; covered_{(5\frac{1}{2} \; days)} = 20\dfrac{53}{10} \; km }$

∴ He'll cover $\rm 20\dfrac{53}{10}$ km in $\rm 5 \dfrac{1 }{2}$ days.

$\rule{200}2$