Chemistry, asked by shivangiprajapati523, 4 months ago

Balance
1 k + H₂O
KOH + H₂
2-tollo C H₂O + O₂ i CO₃+H₂O
37 Fet H₂O + Fenoy the
4- Al, Oz t Hal
* AK.13 + H20
5KI + Pb (NO3)2 РЬІ, + KNO3​

Answers

Answered by goelanjali29
0

Answer:

Lead (II) nitrate + potassium iodide = lead (II) iodide + potassium nitrate

Type of reaction

Bifurcation (metathesis)

Reactive

Lead (II) Nitrate - Pb (NO 3 ) 2

Molar Mass of N2O6Pb Oxidation State of N2O6Pb

Potassium Iodide - KI

Molar Mass of IK Bond Polarity of IK Oxidation State of IK

Product

Lead (II) Iodide - PbI 2

Molar Mass of PbI2 Oxidation State of PbI2

Potassium Nitrate - KNO 3

Molar Mass of KNO3 Oxidation State of KNO3

 

Pb(NO3)2 + KI = PbI2 + KNO3

 

 

 

Instructions

To balance a chemical equation, enter the equation of a chemical reaction and press the balance button. The balanced equation will appear above.

Use the uppercase letter for the first letter in the element and use the uppercase letter for the second letter. Such as: Fe, Au, Co, Br, C, O, N, F.

Ionic charges are not yet supported and will be ignored.

Change irreversible groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O.

Compound states [eg: (s) (aq) or (g)] are not required.

You can use brackets () or [].

Explanation:

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