Balance :
CH₃CCl₃ + O₂ ---> CO₂ + H₂O + Cl₂
hritik916:
4CH3CCl3+11O2---> 8CO2+6H2O+6Cl2
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4ch3ccl3+8o2-->5co2+6h2o+6cl2
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Heya!
CH₃CCl₃ + O₂ ---> CO₂ + H₂O + Cl₂
I will solve this question by Algebraic method!
What you need to do is to assume stoichiometry coefficient of each reactant and product
aCH₃CCl₃ + bO₂ ---> cCO₂ + dH₂O + eCl₂
Here,
a,b,c,d and e are assumed stoichiometry coefficient.
For C -
LHS = RHS
2a = c.........(1)
For H -
LHS = RHS
3a = 2d.........(2)
For Cl -
LHS = RHS
3a = 2e.........(3)
For O -
LHS = RHS
2b = 2c + d..........(4)
Now let's assume that a = 1
then c = 2
3/2 = d
3/2 = e
2b = 2(2) + 3/2
2b = 4 + 3/2
2b = 11/2
b = 11/4
CH₃CCl₃ + 11/4O₂ ---> 2CO₂ + 3/2H₂O + 3/2Cl₂
Let's make it a bit more easy to be understood properly and multiply all the stoichiometry coefficient with 4.
4CH₃CCl₃ + 11O₂ ---> 8 CO₂ + 6H₂O + 6Cl₂
#Shati
#Brainly benefactor
CH₃CCl₃ + O₂ ---> CO₂ + H₂O + Cl₂
I will solve this question by Algebraic method!
What you need to do is to assume stoichiometry coefficient of each reactant and product
aCH₃CCl₃ + bO₂ ---> cCO₂ + dH₂O + eCl₂
Here,
a,b,c,d and e are assumed stoichiometry coefficient.
For C -
LHS = RHS
2a = c.........(1)
For H -
LHS = RHS
3a = 2d.........(2)
For Cl -
LHS = RHS
3a = 2e.........(3)
For O -
LHS = RHS
2b = 2c + d..........(4)
Now let's assume that a = 1
then c = 2
3/2 = d
3/2 = e
2b = 2(2) + 3/2
2b = 4 + 3/2
2b = 11/2
b = 11/4
CH₃CCl₃ + 11/4O₂ ---> 2CO₂ + 3/2H₂O + 3/2Cl₂
Let's make it a bit more easy to be understood properly and multiply all the stoichiometry coefficient with 4.
4CH₃CCl₃ + 11O₂ ---> 8 CO₂ + 6H₂O + 6Cl₂
#Shati
#Brainly benefactor
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