balance charge on cr2o72-gives 2cr3+
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☆ Oxidation no of O is -2
☆ Cr2O7 = -2
☆ Cr2 + (-2×7) = -2
☆ Cr2 = +12
☆ Cr oxidation no = +6 in dichromate anion at reactants
☆ Cr= +3 at products
It is reduction process which cr gains 3e
So,
6e + Cr2O7^-2 => 2Cr^+3
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