Chemistry, asked by sohamroy31, 8 months ago

balance =
iron III chloride + water + sulphur dioxide = iron II chloride + sulphuric acid + hydrochloric acid

Answers

Answered by Anonymous

4

2FeCl3 + 2H2O + SO2 → 2FeCl2 + H2SO4 + 2HCl

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Answered by pjahnabi007

1

Answer:

2FeCl3 + 2H2O + SO2 → 2FeCl2 + H2SO4 + 2HCl

. Iron(III) chloride react with water and sulfur dioxide to produce iron(II) chloride, sulfuric acid and hydrogen chloride

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