Chemistry, asked by raminder1, 1 year ago

balance it in detail..........

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raminder1: don't answer if you don't know properly
3feb: If you can't understand it it's your problem..
raminder1: hlo 3fed
raminder1: feb*
raminder1: "dont.......properly"....this comment not for you
3feb: Ok...then..

Answers

Answered by 3feb
1
This is the oxidation of ethanal to ethanoic acid. I will assume acidic conditions.

Ist set up the 1/2 equations:

CH3C−1HO→CHCOO+1H

You can see from the oxidation numbers in red that the H atom in question goes from -1 to +1. This means it must give out 2 electrons.

We add water on the left and H+ ions and electrons on the right ⇒

CH3CHO+H2O→CHCOOH+2H++2e...........(1)

Now for the dichromate(VI):

+6Cr2O2−7→2+3Cr3+

So we have:

(2×+6)=+12→(2×+3)=+6

i.e +12→+6 so this requires 6 electrons to effect this change.

We add H+ ions on the left to mop up the oxygens⇒

Cr2O2−7+14H++6e→2Cr3++7H2O..............(2)

We now need to x (1) by 3 to get the electrons to balance⇒

3CH3CHO+3H2O→3CHCOOH+6H++6e..........(3)

Now we add both sides of (2)and(3) together:

Cr2O2−7+14H++6e+3CH3CHO+3H2O→2Cr3++7H2O+3CH3COOH+6H++6e

This cancels down to:

Cr2O2−7+8H++3CH3CHO→2Cr3++4H2O+3CH3COOH

therefore.Answer:

Cr2O2−7+8H++3CH3CHO→2Cr3++4H2O+3CH3COOH..plz Mark it in Brainliest..


raminder1: thankyou so mch
raminder1: but i wanted with oxidation method
3feb: Mark in Brainliest
raminder1: but i wanted with oxi methd
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