balance P + hnO3 -----> h3PO4 +NO2 + H2O by oxidation number method
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•Here we have to balance
P + HNO3 -----> H3PO4 +NO2 + H2O
In left hand side ,the oxidation number of P is 0
and in right hand side, the oxidation number of P is +5
Thus, In left hand side,the oxidation number of N is +5 and In right hand side , the oxidation number of N is +4
and
P(0) - 5e——› P(+5)
N(+5) +e ——› N(+4)
now
P(0) - 5e——› P(+5 × 1)
N(+5) +5e ——› N(+4 × 5)
so
P(0) - 5e = P(+5) ....(1)
N(+5) +5e = 5N(+4) .....(2)
by addition of (1) & (2) is
P(0)+5N(+5) = P(+5) + 5N(+4)
The balance would be
P+ 5HNO3 = H3PO3 + 5NO2 + H2O
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