Question

balance potassium bromide +barium chloride

Answer 1

2KBr + BaI     =  2KI + BaBr
                  2                       2     

Answer 2

Hi friend,

You can solve this question by hit and trial method and also by Algebraic method or a,b,c method

Let's describe about Algebraic method! because it's easiest method to solve any kind of problems based on balancing.

aKBr + bBaCl2 ----› cKCl + dBa(Br)2

Here marked a,b,c and d are the assumed stoichiometry coefficient.

In balancing LHS = RHS

For K --›
a = c.....(1)
For Br --›
a = 2d.....(2)
For Ba --›
b = d.......(3)
For Cl --›
2b = c.......(4)

Let's for once assume that the value of a = 1 then :-
c = 1
b = 1/2.......(4)
d = 1/2......(3)

KCl + 1/2BaCl2 --› KCl + 1/2 BaBr2

(b) ZnCO3 ---› ZnO + CO2
This equation is already balanced.Since LHS = RHS

(c) H2 + Cl2 ---› HCl
This can be easily solved by hit and trial method
H2 + Cl2 ---› 2HCl

(d) aMg + bHCl ---› cMgCl2 + dH2
Solve it by hit and trial method and one more time by that Algebraic method. so that you can understand that easily.

for Mg --›
a = c....(1)
for H --›
b = 2d.....(2)
for Cl --›
b = 2c......(3)

Now assume that a = 1 then :
c = 1......(1)
b = 2.....(3)
d = 1.....(2)

So, your equation is ready
Mg + 2HCl --› MgCl2 + H2

#Your Q10 is similar to Q8
By Algebraic method you can do it easily.

Q9)
Exothermic process is a process in which energy is released.
So,When the oxidation of glucose present in our food takes place high amount of energy is released along with CO2.

C6H12O6 + O2 ---› CO2 + H2O + energy