Chemistry, asked by jbonnin52, 1 year ago

Balance the chemical equation and create a Matrix and solve for a general solution.

KNO3 +C12H22O11→ N2 +CO2 + H2O+K2CO3


*Please Show all working out of matrices and REF

Answers

Answered by rajnandb383
0

KNO3 + C12H22O11 → N2 + CO2 + H2O + K2CO3

For complicated reactions like this, your only practical option is algebra.

So assign variables to each reactant and

Product:

a KNO3 + b C12H22O11 → c N2 + d CO2 + e H2O + f K2CO3

Now write an equation for the balancing of each element:

K: a = 2f

N: a = 2c

O: 3a + 11b = 2d + e + 3f

C: 12b = d + f

H: 22b = 2e

Now you have five equations in six unknowns. Use whatever algebraic method for solving simultaneous equations you like best. Here's mine:

Substitute the value equivalent to "a" from the first equation into the third and fourth equations above:

3a + 11b = 2d + e + 3a/2

12b = d + a/2

Combine like terms in the longer equation:

3a/2 + 11b = 2d + e

Solve the shorter equation for a/2:

a/2 = 12b - d

Multiply by 3:

3a/2 = 36b - 3d

Substitute this value for 3a/2 into the previous, longer equation:

( 36b - 3d) + 11b = 2d + e

Combine like terms:

47b = 5d + e

Divide the original "H:" equation by 2:

11b = e

Substitute this value for e into the previous equation:

47b = 5d + 11b

Combine like terms:

36b = 5d

Arbitrarily set d = 1 [What d really should be will be determined later. And for that matter, alternatively b could be 1 instead and it would all work out the same in the end.]

36b = 5

b = 5/36

Start substituting d = 1 and b = 5/36 into the previous equations and solving for the other variables as you go:

11 (5/36) = e

e = 55/36

a/2 = 12(5/36) - 1

a = 4/3

4/3 = 2c

c = 2/3

4/3 = 2f

f = 2/3

So altogether one solution to the original simultaneous equations is:

a = 4/3, b = 5/36, c = 2/3, d = 1, e = 55/36, f = 2/3

These numbers balance the original chemical equation, but fractional coefficients are forbidden, so multiply all the variables by 36 to eliminate the fractions:

a = 48, b = 5, c = 24, d = 36, e = 55, f = 24

Substitute these values into the original chemical equation to see it correctly

balanced:

48 KNO3 + 5 C12H22O11 → 24 N2 + 36 CO2 + 55 H2O + 24 K2CO3

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