Balance the chemical equation and Idently
the type of chemical reaction :
H202(1) - H2O(1) 402(g)
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Explanation:
sing Hess's law of constant heat of summation and given: 1) H2O(1)H2O(g) AH = -44.1k] II) CH3COCH3(1) + 402(g) 3CO2(g) + 3H2O(1) AH=-1787 kJ III) CH3COOH(I) + 2O2(g) → 2CO2(g) + 2H2O(1) AH=-835 kJ determine the enthalpy of reaction for CH3COCH3 (1) + 2O2(g) → CH3COOH(I) + CO2(g) + H2O(g)
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