Question

Balance the chemical equation by using LCM method Pcl5+H2o=H3po4+Hcl

Answer 1

Answer

PCl5 + 4H2O → H3PO4 + 5HCl

Answer 2

Balanced equation $PCl5 + 4H2O --- H3PO4 + 5HCl$

Explanation:

$PCl5 + H2O----- H3PO4 + HCl$

Balancing the equation  using LCM method

We calculate the Left side:

P = 1,Cl = 5,H = 2,O = 1

Right side:

P = 1,Cl = 1,H = 3 + 1 O = 4

Now starting to balance the equation Start balancing the easiest element, in this case, the Cl.

Left side:

P = 1,Cl = 5,H = 2,O = 1

since HCl is a substance, we can multiply its H by 5.

Right side:

P = 1,Cl = 1 x 5 = 5,H = 3 + (1 x 5) = 8,O = 4

Now the H atom on the left side is not balanced with the right side, we have to multiply the H on the left side by 4.

Left side:

P = 1,Cl = 5,H = 2 x 4 = 8,O = 1 x 4 = 4

Again, since H2O is a substance, you also need to multiply its O by 4.

Right side:

P = 1,Cl = 1 x 5 = 5,H = 3 + (1 x 5) = 8,O = 4

Balanced equation is

$PCl5 + 4H2O --- H3PO4 + 5HCl$

Phosphoric Acid + Hydrogen Chloride = Phosphorus Pentachloride + Water.