Question

balance the chemical equation,calcullate the number of molecules of so2 gas when liberated on consuming of 3 mol of oxygen as at s.t.p​

Answer 1

Answer:

cu2s+o2------->cu2o+so2

Answer 2

The number of molecules of sulfur dioxide gas liberated are $1.807\times 10^{24}$

Explanation:

We are given:

Moles of oxygen gas = 3 moles

The balanced chemical equation for the reaction of copper (I) sulfide and oxygen gas follows:

$2Cu_2S+3O_2\rightarrow 2Cu_2O+2SO_2$

By Stoichiometry of the reaction:

3 moles of oxygen gas produces 2 moles of sulfur dioxide

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, 2 moles of sulfur dioxide will contain = $(3\times 6.022\times 10^{23})=1.807\times 10^{24}$ number of molecules

Learn more about mole concept and stoichiometry:

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