Question

balance the equation​

Answer 1

Explanation:

in the first eq put 2 in front of HN03 ( ie 2HNO3)in reactant and in product put 2 in H20 the eq will be balanced

in 2nd eq put 2 in front of NaOH in reactant and in product put 2 in H2O the eq will be balanced

In 3rd eq the eq is already balanced so no changes

In 4th eq put 2 in Hcl in the product then the eq will eb balanced

in 5th eq put 2in Na2Co3 and 4 in HCl on the reactant side and put 4 in NACl and put 2 in H2O and 2 in Co2 on product side the eq will be balanced

in 6th put 3 In Fe on and 4 in H2O on reactant side and 4in H2 on product side the eq will be balanced

Answer 2

Answer:

join baby fast I have answer my id and password in another question