Question

balance the equation??​

Answer 1

Answer:

Explanation:

Given,

$Cu+HNO_3 \rightleftharpoons Cu(NO_3)_2 + NO + H_2O$

Solution :-

1) The skeletal equation is written as :-

$Cu+HNO_3 \rightleftharpoons Cu(NO_3)_2 + NO + H_2O$

2) Focusing on oxidation number :-

for :-

Cu = 0

in HNO_3 :-

H = +1

N = +5

O = -2

in Cu(NO_3)_2

Cu = +2

N = +5

O = - 2

in NO :-

N = +2

O = -2

in H_2O :-

H = +1

O = - 2

3) Locating the atoms undergoing change in oxidation numbers :-

Both Cu and N goes change in their oxidation number .

4) Determining the change in oxidation numbers :-

$3Cu + 2NO_3^- \rightleftharpoons 3Cu^{2+}+2NO+2H_2O$

5) Cris - crossing these changes in oxidation numbers :-

Cu :- Increase is  2

N :- Decrease is 3

6)Balancing Hydrogen and oxidation atoms :-

$3Cu+8HNO_3 \rightleftharpoons 3Cu(NO_3)_2+2NO+4H_2O$

Hence the balanced equation is :-

$3Cu+8HNO_3 \rightleftharpoons 3Cu(NO_3)_2+2NO+4H_2O$