Question

Balance the equation by oxidation number method : (Cr2O7-2)+(Fe+2)+(H+)=(Fe+3)+(Cr+3)+H2O

Answer 1

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Fe 2+ +Cr 2 O 72−+H +

⟶Fe 3++Cr 3+ +H 2O

(1) Oxidation: Fe 2+

→Fe 3+

Reduction:

Cr+62 O 72−

⟶ C+3 r 3+

(2) Balancing the atoms

Fe 2+

⟶Fe 3+

Cr 2O 72−+14H +

⟶2Cr 3+ +7H 2 O

(3) Balance the charge

Fe 2+

⟶Fe 3+ +e −

⟶(1) Cr 2 O 72− +14H ++6e −

⟶2Cr 3++7H 2O⟶(2)

(4) Equation (1) ×6+ Equation (2) ×1 Balancing electrons.

6Fe 2+ +Cr 2 O 72−+14H + +6e −

⟶6Fe 3+ +2Cr 3+ +6e – +7H 2 O

(5) Simplifying;

6Fe 2+ +Cr 2 O 72− +14H

⟶6Fe 3+ +2Cr 3+ +7H 2 O

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