Question

balance the equation: (Cr2O7-2)+(Fe+2)+(H+)=(Fe+3)+(Cr+3)+H2O

Answer 1

ANSWER:

6F$e^{2+}$ + Cr$_{2}$$O^{2-}_{7}$ + 14$H^{+}$ → 6F$e^{3+}$ + 2$Cr^{3+}$ + 7H$_{2}$O

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