Question

balance the equation :- ferric oxide reacts with sulphuric acid and give ferric sulphate and water.

Answer 1

This will be answer for this question

Answer 2

The basic reaction that takes place is given by the following reaction shown:

$Fe_{2}O_{3} +H_{2}SO_{4}$ {Addition of ferric oxide to sulfuric acid} $\rightarrow Fe_{2} (SO_{4})_{3} + H_{2}O$ {that is ferric sulphate and water}

Now we see the basic reaction does not balance the molecules on either sides hence the reaction should be balanced.

Since on right there are three molecules of sulphur. Hence on left there should be three molecules of sulphuric acid and since this makes 6 hydrogen atoms and bright side water should be three molecules.

So the balance equation now becomes ,

                                $Fe_{2}O_{3} +3H_{2}SO_{4} \rightarrow Fe_{2} (SO_{4})_{3} + 3H_{2}O$

To know more:

Balance the chemical equation ferric oxide react with sulphuric acid to give ferric sulphate + water

https://brainly.in/question/6241752