balance the equation given above
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Oh Good. Wonderful Equation to balance. Most of the students used to confuse in this equation, How to balance it.
Balancing.
Steps of Balancing from Oxidation number method.
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- Step 1. First Write the Given Redox Reaction.
Cr(OH)₃ + IO₃⁻ ------- I⁻ + CrO₄²⁻ (write the oxidation state also.)
- Step2. Identify Oxidation and Reduction half Reaction.
IO₃⁻ ------- I⁻ [Reduction] [Changes by 6 unit]
(Oxidation number of Iodine is changing.)
Cr(OH)₃ ------- CrO₄²⁻ [Oxidation] [Changes by 3 unit]
(Oxidation number of the Cr is changing)
- Step 3 .Multiply 1st equation by 1 and second equation by 2.
2Cr(OH)₃ ------- 2CrO₄²⁻
IO₃⁻ ------- I⁻
- Step 4. Now, Add both the equations,
∴ 2Cr(OH)₃ + IO₃⁻ ------- 2CrO₄²⁻ + I⁻
- Step 5. Now, Add the OH⁻ ions on L.H.S. and Water on R.H.S. , since this reaction will be in basic medium.
∴ 2Cr(OH)₃ + IO₃⁻ + 4OH⁻ ------- 2CrO₄²⁻ + I⁻ + 5H₂O
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