Question

Balance the equation: Potassium Bicarbonate + Sulphuric acid = Potassium Sulphate + Carbon dioxide + water

Answer 1

$\bigstar$ Answer $\bigstar$

$\checkmark$ Given Chemical Reaction:

Potassium Bicarbonate + Sulphuric acid → Potassium Sulphate + Carbon dioxide + Water

$\checkmark$ Chemical Equation:

$\red{\sf KHCO_{3}+H_{2}SO_{4} \longrightarrow K_{2}SO_{4}+CO_{2}+H_{2}O}$

$\checkmark$ Balanced Chemical Equation:

$\blue{\sf 2\,KHCO_{3}+H_{2}SO_{4} \longrightarrow K_{2}SO_{4}+2\,CO_{2}+2\,H_{2}O}$

We know that,

A reaction is said to be Balanced when the number of the atoms of elements in the reactants side is equal to that of the products side.

Therefore,

$\star$ For Verification of Balanced Equation

Both Left-Hand-Side (Reactants) and Right-Hand-Side (Products) of the Chemical Equation contains

$\blue{\sf \implies K=2 \ atoms}$

$\green{\sf \implies H=4 \ atoms}$

$\red{\sf \implies C=2 \ atoms}$

$\orange{\sf \implies O=10 \ atoms}$

$\pink{\sf \implies S=1 \ atoms}$

Since,

The number of the atoms of the elements in the reactants side is equal to that of the products side.

Hence,

$\star$ The Chemical Equation is Balanced

Answer 2

Explanation:

ᴀɴsᴡᴇʀ:

Firstly, you must write out your products and reactants in molecular form.

K2CO3 (aq) + H2SO4 (aq) = K2SO4(aq) + CO2 (g) + H20

Now you count each element for both the product and the reactant side.

✍Product Side:

➡K = 2

➡C=1

➡H=2

➡O=7

➡S=1

✍Reactant Side:

➡K=2

➡C=1

➡H=2

➡O=7

➡S=1

The reaction is now balanced