balance the equation.
Potassium bromide + barium iodide - potassium iodide+ barium bromide
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2Kbr + BaI2 → 2KI + BaBr2
reactant side :-
K = 1×2 = 2
Br = 1×2 = 2
Ba = 1
I = 2
product side :-
K = 1×2 = 2
Br = 2
Ba = 1
I = 1×2 = 2
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