Question

Balance the equation with proper steps and write the number of atoms of each element in the reactant and product side.

1) Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O

Answer 1

hey there

Refer to attachment

Answer 2

The balanced chemical equation is :

$\mathsf{2Al(OH)_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+6H_2O}$

Proper steps to balance the given equation :

↪ First always balance the elements other than oxygen . We will start from the left hand side first .

↪ Balance the aluminium element .

↪ There are two atoms on the left and one on the right .

↪ So balance the aluminium on the left by putting 2 beside Al .

↪ Now we will focus on sulphur .

↪ There are 12 sulphur atoms on the right while there are 4 on the left .

↪ So we put 3 before H so that the number of sulphur atoms become 12 again .

↪ Now at last there is hydrogen and oxygen to balance .

↪ We balance the number of hydrogen by putting 6 in front of H at the last .

↪ The oxygen will be automatically balanced .

Reactant :

➡ Number of Al = 2

➡ Number of H = 6 + 6 = 12

➡ Number of S = 3

➡ Number of O = 4 × 3 + 6 = 12 + 6 = 18

Product :

➡ Number of Al = 2

➡ Number of H = 6 × 2 = 12

➡ Number of S = 3

➡ Number of O = 4 × 3 + 6 × 1 = 12 + 6 = 18

NOTE :

In a balanced chemical equation . the number of each elements in reactants is equal in both reactants and products .