Question

Balance the equations Mg+Co2=Mgo+c

Answer 1

2Mg+CO2=2Mgo+c is the balancing form of above equation

Answer 2

Answer:

2Mg (s) + CO₂ (g) ⟶ 2MgO (s) + C (s)

Explanation:

Mg + CO₂ ⟶ MgO + C

In this reaction, magnesium ( Mg ) reacts with carbon dioxide ( CO₂ ) to form magnesium oxide ( MgO ) and carbon ( C ).

Atoms in reactants side:

• Mg = 1
• C = 1
• O = 2

Atoms in products side:

• Mg = 1
• C = 1
• O = 1

By law of conservation of mass, we know that the number of atoms of each element in reactants side must be equal to number of atoms in products side.

To make the number of atoms equal in both sides, we multiply MgO by 2 as there is 1 atom of oxygen missing in product side.

Mg + CO₂ ⟶ 2MgO + C

Atoms in reactants side:

• Mg = 1
• C = 1
• O = 2

Atoms in products side:

• Mg = 2
• C = 1
• O = 2

Now, 1 atom of magnesium is missing in reactant side, so we multiply Mg by 2 to make both sides equal in number of atoms.

2Mg (s) + CO₂ (g) ⟶ 2MgO (s) + C (s)

This is the balanced chemical equation.