Question

balance the following C3 H8 +02 CO₂ + H₂O​

Answer 1

Answer:

First of all, to balance these equations, list the number of each atom, for both sides of the equation. In this example, it would be:

 

Carbon: 3                                                        Carbon: 1

Hydrogen: 8                                                    Hydrogen: 2

Oxygen: 2                                                       Oxygen: 3

The first step would be to balance out the carbons on the products side by multiplying CO2 by 3. The new equation will be 

C3H8 + 02 ----> 3CO2 + H20

Now, the carbons are balanced, we will look at the hydrogens. We can multiply the number of waters on the product side by 4, to make 4 H20 molecules. This gives both sides of the equation 8 hydrogens. Next we can check our oxygens. There will be 10 oxygens on the products side and 2 on the reactants so to balance these out, we multiply the 02 on the reactants side by 5. 

The final equation will be C3H8 + 502 ----> 3CO2 + 4H20. 

Answer 2

Answer:

First of all, to balance these equations, list the number of each atom, for both sides of the equation. In this example, it would be:

Carbon: 3 Carbon: 1

Hydrogen: 8 Hydrogen: 2

Oxygen: 2 Oxygen: 3

The first step would be to balance out the carbons on the products side by multiplying CO2 by 3. The new equation will be

C3H8 + 02 ----> 3CO2 + H20

Now, the carbons are balanced, we will look at the hydrogens. We can multiply the number of waters on the product side by 4, to make 4 H20 molecules. This gives both sides of the equation 8 hydrogens. Next we can check our oxygens. There will be 10 oxygens on the products side and 2 on the reactants so to balance these out, we multiply the 02 on the reactants side by 5.

The final equation will be C3H8 + 502 ----> 3CO2 + 4H20.