balance the following chemical equation
Answers
Answer:
hey dear here u go~
Explanation:
A
l
B
r
3
+
K
2
S
O
4
→
K
B
r
+
A
l
2
(
S
O
4
)
3
How I balance equations is by first of all dividing the equation into two parts - reactants and products.
Reactants
Al = 3
Br = 3
K = 2
S = 1
O = 4
Products
Al = 2
Br = 1
K = 1
S = 3
O = 12
Remember all atoms within the brackets get multiplied by the number outwith them.
Step 1
Put a 6 before KBr
A
l
B
r
3
+
K
2
S
O
4
→
6
K
B
r
+
A
l
2
(
S
O
4
)
3
Step 2
Put a 2 before
A
l
B
r
3
- this has now balanced the number of Aluminium and Bromine atoms.
2
A
l
B
r
3
+
K
2
S
O
4
→
6
K
B
r
+
A
l
2
(
S
O
4
)
3
Step 3
Put a 3 before
K
2
S
O
4
This balances the Potassium, Sulphur and Oxyen
2
A
l
B
r
3
+
3
K
2
S
O
4
→
6
K
B
r
+
A
l
2
(
S
O
4
)
3
Now check the reactants and products:
Reactants
Al - 2
Br - 6
K - 6
S - 3
O - 12
Products
Al - 2
Br - 6
K - 6
S - 3
O - 12
We have now successfully balanced the equation
I hope this helps!A
l
B
r
3
+
K
2
S
O
4
→
K
B
r
+
A
l
2
(
S
O
4
)
3
How I balance equations is by first of all dividing the equation into two parts - reactants and products.
Reactants
Al = 3
Br = 3
K = 2
S = 1
O = 4
Products
Al = 2
Br = 1
K = 1
S = 3
O = 12
Remember all atoms within the brackets get multiplied by the number outwith them.
Step 1
Put a 6 before KBr
A
l
B
r
3
+
K
2
S
O
4
→
6
K
B
r
+
A
l
2
(
S
O
4
)
3
Step 2
Put a 2 before
A
l
B
r
3
- this has now balanced the number of Aluminium and Bromine atoms.
2
A
l
B
r
3
+
K
2
S
O
4
→
6
K
B
r
+
A
l
2
(
S
O
4
)
3
Step 3
Put a 3 before
K
2
S
O
4
This balances the Potassium, Sulphur and Oxyen
2
A
l
B
r
3
+
3
K
2
S
O
4
→
6
K
B
r
+
A
l
2
(
S
O
4
)
3
Now check the reactants and products:
Reactants
Al - 2
Br - 6
K - 6
S - 3
O - 12
Products
Al - 2
Br - 6
K - 6
S - 3
O - 12
We have now successfully balanced the equation
I hope this helps!