Question

Balance the following chemical equation (if necessary):
Al(s)+HCl(aq)--->H2(g)+AlCl3(aq

Answer 1

Answer:

2Al + 6HCl ---> 3H2 + 2AlCl3

Answer 2

Answer :-

2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)

Explanation:

Al(s)+HCl(aq) →AlCl3 (aq)+H2(g)

is unbalanced.

Balance Cl.

There are 3 Cl atoms on the product side and 1 on the reactant side. Add a coefficient of 3 in front of

HCl .

Al(s)+3HCl(aq)→AlCl3(aq)+H2(g)

There are now 3 Cl atoms on both sides.

Balance H.

There are 3 H atoms on the reactant side and 2 on the product side. 3 and 2 are multiples of 6. So change the coefficient in front of HCl from 3 to 6, and add a coefficient of 3 in front of the H2 .

Al(s)+6HCl(aq)→AlCl3(aq)+3H2(g)

There are now 6 H atoms on both sides.

Go back to the Cl. There are now 6 Cl on the reactant side and 3 on the product side. Add a coefficient of 2 in front of AlCl3 .

Al(s)+6HCl(aq)→ 2AlCl3(aq)+3H2(g)

There are now 6 Cl atoms on both sides.

Balance the Al

There is 1 Al on the reactant side and 2 Al on the product side. Add a coefficient in front of Al on the reactant side.

2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)

There are now 2 Al on both sides and the equation is balanced.

Reactants:

2 Al atoms,6 H atoms,6 Cl atoms

Products:

2 Al atoms,6 H atoms,6 Cl atoms