Balance the following chemical equation
in the acidic medium by oxidation
number method MnO4(aq) + C2H2O4(aq) + H+ - Mn2(aq) + Co2 + H2O (l)
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Answer:
MnO
4
−
+C
2
H
2
O
4
⇌Mn
2
+CO
2
+H
2
O
Mn
+7
O
−2
4
−
+
C
2
+3
H
2
+1
O
4
−2
⇌
Mn
2
0
+
C
+4
O
2
−2
+
H
2
+
O
−2
Oxidation:
C
2
+3
H
2
1
O
4
−2
⟶
C
+4
O
2
−2
Rediuction:
Mn
+7
O
4
−
−2
⟶
Mn
2
0
Balancing on both sides;
O:C
2
H
2
O
4
⟶2CO
2
+2H
+
R:2MnO
4
−
⟶Mn
2
+8H
2
O
⇒O:C
2
H
2
O
4
⟶2CO
2
+2H
+
+2e
−
R:14e
−
+2MnO
4
−
+16H
+
⟶Mn
2
+8H
2
O
__________________________________________
7C
2
H
2
O
4
⟶14CO
2
+14H
+
+14e
−
2MnO
4
−
+16H
+
+14e
−
⟶Mn
2
+8H
2
O
⇒7C
2
H
2
O
4
+2MnO
4
−
+16H
+
+14e
−
⇌14CO
2
+MN
2
+14H
+
+8H
2
O+14e
−
(Refer to Image)
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