Question

balance the following chemical equation: lead acetate reacts with hydrogen sulphide to form acetic acid and lead sulphide​

Answer 1

Answer:

Pb(CH3COO)2 + 2HCl → PbCl2 + CH3COOH This is a Double Displacement reaction. (b) 2Na + 2C2H5OH → 2C2H5ONa + H2 This is a Displacement reaction. (c) Fe2O3 + 3CO → 2Fe + 3CO2 This is a redox reaction. (d) 2 H2S + O2→ 2 S + 2 H2O This is a replacement reaction.