Question

Balance the following chemical equation:
Pb(NO3)2(s) PbO(s) + NO2(g) + O2 (g)

Answer 1

Answer:

pb 2034v ss pb0 = no2 +h20

Explanation:

Answer 2

2Pb(NO3)2 --> 2PbO + 4NO2 + O2

Explanation:

To balance the given equation of the decomposition of lead (II) nitrate, let's start by counting atoms of each element separately on the left and right-hand sides.

To start on the left, we have one Pb, two nitrogen and 6 oxygen atoms.

On the right, we have one lead, one nitrogen and 5 oxygen atoms.

To balance an equation means we should have equal number of atoms of the same element on both sides of the equation.

So if we add 2 in front of lead nitrate, we will have 2 lead, 4 nitrogen and 12 oxygen atoms on the left hand side.

Let's add the corresponding numbers on the right-hand side, so we get  2 lead, 4 nitrogen and 12 oxygen atoms here as well.

Then the equation will be balance as below:  

2Pb(NO3)2 --> 2PbO + 4NO2 + O2