Balance the following chemical equations
(a) C3H8 + O2 → H2O +CO2
(b) CH4 + O2 → CO2 +H2O
(c) NaHCO3 → Na2CO3 +H2O +CO2
(d) N2 +H2 → NH3
(e) CO2 + H2O → C6H12O6 + O2
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Answered by
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Answer:
a)
(There will be no need for state symbols.) Now, the carbons are balanced, we will look at the hydrogens. We can multiply the number of waters on the product side by 4, to make 4 H20 molecules.
b) The combustion of methane or octane is exothermic; it releases energy. CH4 + 2 O2 → CO2 + 2 H2O + energy The energies of the products are lower than the energiies of the reactants.
Answered by
1
Answer:
(a) C3H8 + 5O2 = 4H2O + 3CO2
(b) CH4 + 2O2 = CO2 + 2H2O
(c) PLEASE WRITE EQUATION CAREFULLY
(d) N2 +. 3H2 =. 2NH3
(e) 6CO2 +. 6H2O = C6H12O6 +. O2
Explanation:
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