Balance the following chemical equations.
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Answer:
2NaOH + H2SO4 —› Na2SO4 +2 H2O
Explanation:
There are 2 Na in R.H.S while only 1 Na in L.H.S
so we have to balance that,
2NaOH + H2SO4 —› Na2SO4 +H2O
There is only 1 S in L.H.S and also in R.H.S
so we don't have to balance that
Now,
In L.H.S
there is 2 O in NaOH and 4 O in H2SO4
Total O in L.H.S is 6
In R.H.S
there is 4 O in Na2SO4 and 1 O in H2O
Total O in R.H.S is 5
To balance O we have to put 1 more O in R.H.S
So,
2NaOH + H2SO4 —› Na2SO4 +2 H2O
In L.H.S
there is 2 H in NaOH and 2 H in H2SO4
Total H in L.H.S is 4
In R.H.S
there is 4 H in H2O
Both L.H.S and R.H.S is now,
L.H.S. R.H.S
Na 2 2
S 1 1
O 6 6
H 4 4
Ans. 2NaOH + H2SO4 —› Na2SO4 +2 H2O
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