Question

balance the following equation:​

Answer 1

${\boxed{\boxed{\red{\rm{SOLUTION :- }}}}}$

$\leadsto$ (1) 2Fe + 3cl2 -----> 2fecl3

$\leadsto$ (2) h2s + cl2-------> s + 2hcl

$\leadsto$ (3) 2fecl2 + cl2 -----> 2fecl3

$\leadsto$ (4) co2 + c -----> 2co

$\leadsto$ (5) 2khco3-----> k2co3 + h2o + co2

$\leadsto$ (6) 4k + co2 ----->2k2o + c

Answer 2

Here is your answer dear⛄

• $\sf\underline\red{ Unbalanced \: equation }$ :-

① Fe + ${Cl}_{2}$ ➺ ${FeCl}_{3}$

• $\sf\underline\red{ Balanced \: equation }$ :-

2Fe + ${3Cl}_{2}$ ➺ ${2FeCl}_{3}$

• $\tt\underline\blue{ Unbalanced \: equation }$ :-

② ${H}_{2}{S}$ + ${Cl}_{3}$ ➺ S + HCl

• $\tt\underline\blue{ Balanced equation }$ :-

${H}_{2}{S}$ + ${Cl}_{2}$ ➺ S + 2HCl

• $\bf\underline\pink{ Unbalanced \: equation }$ :-

③ ${FeCl}_{2}$ + ${Cl}_{2}$ ➺ ${FeCl}_{3}$

• $\bf\underline\pink{ Balanced \: equation }$ :-

${2FeCl}_{2}$ + ${Cl}_{2}$ ➺ ${2FeCl}_{3}$

• $\rm\underline\green{ Unbalanced \: equation }$ :-

④ ${CO}_{2}$ + C ➺ CO

• $\rm\underline\green{ Balanced equation }$ :-

${CO}_{2}$ + C ➺ 2CO

• $\sf\underline\red{ Unbalanced \: equation }$ :-

⑤ ${KHCO}_{3}$ ➺ ${K}_{2}{CO}_{3}$ + ${H}_{2}{O}$ + ${CO}_{2}$

• $\sf\underline\red{ Balanced \: equation }$ :-

${2KHCO}_{3}$ ➺ ${K}_{2}{CO}_{3}$ + ${H}_{2}{O}$ + ${CO}_{2}$

• $\tt\underline\purple{ Unbalanced \: equation }$ :-

⑥ K + ${CO}_{2}$ ➺ ${K}_{2}{O}$ + C

• $\tt\underline\purple{ Balanced \: equation }$

4K + ${CO}_{2}$ ➺ ${2K}_{2}{O}$ + C

$\huge\colorbox{pink}{MysticalGiggles}$