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Balance the following equation: __BaCl₂ + __Na₂SO₄ → __NaCl + __BaSO₄

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Answered by Anonymous
35

Given to balance the equation:-

BaCl₂ + Na₂ SO₄ → NaCl + BaSO₄

Balanced equation is :-

BaCl₂ + Na₂ SO₄ → 2NaCl + BaSO₄

EXPLANATION:-

Lets balance the equation by Hit and trail method .First Lets find how many atoms of elements present in reactants and products .

In reactants :-

Barium (Ba) - 1 atom

Chlorine(Cl) - 2 atoms

Sodium (Na) - 2 atoms

Sulphur (S) - 1 atom

Oxygen (O) - 4 atoms

In products :-

Barium (Ba) - 1 atom

Chlorine(Cl) - 1 atom

Sodium (Na) - 1 atom

Sulphur (S) - 1 atom

Oxygen (O) - 4 atoms

So, by this observation

Barium(Ba), Sulphur(S) , Oxygen(O) have same number of atoms in reactants and products

So, we need to balance the other elements that were Sodium, Chlorine

So, for balancing this If we add two moles in the products for NaCl => 2NaCl

After adding this all atoms can be balanced

BaCl₂ + Na₂ SO₄ → 2NaCl + BaSO₄ => Balanced reaction

After balancing all reactants of atoms and products atoms were same

After balancing :-

In reactants :-

Barium (Ba) - 1 atom

Chlorine(Cl) - 2 atoms

Sodium (Na) - 2 atoms

Sulphur (S) - 1 atom

Oxygen (O) - 4 atoms

In products :-

Barium (Ba) - 1 atom

Chlorine(Cl) - 2 atoms

Sodium (Na) - 2 atoms

Sulphur (S) - 1 atom

Oxygen (O) - 4 atoms

Thus balanced !

Answered by Anonymous
46

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