Balance the following equation by ion electron method: Na₂S₂O3+I₂-Na₂S.O6 +Nal
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Na2S2O3 +I2 = Na2S4O6+NaI balance the equation by ion electron method.
here we see iodine , I2 is reduced (as oxidation number changes from 0 to -1) and sulphur is oxidised. ( as oxidation number of s changes from +2 to +2.5)
now adding ions both sides in equations (1) and (2)
then, ....(1)
and ....(2)
now adding equations (1) and (2) we get,
This is our balanced chemical equation.
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