Question

Balance the following equation by ion electron method.
H2S + Mn O4- + H + --------------- S + Mn 2+ + H2O
AsO3- + IO3- -------------- AsO43- + I -
​​​​​​​Please answer it till tomorrow morning. It's really very urgent

Answer 1

Answer:

there is your answer

Explanation:

The unbalanced redox equation is as follows:

AsO33−+MnO4−→AsO43−+MnO2+H2O

All atoms other than H and O are balanced.

The oxidation number of As changes from +3 to +5. The change in the oxidation number of As is +2.

The oxidation number of Mn changes from +7 to +4. The change in the oxidation number of Mn is 3.

The increase in the oxidation number is balanced with decrease in the oxidation number by multiplying

AsO33− and AsO43− with 3 and multiplying MnO4− and MnO2 with 2.

3AsO33−+2MnO4−→3AsO43−+2MnO2+H2O

O atoms are balanced.

3AsO33−+2MnO4−→3AsO43−+2MnO2+H2O

Hydrogen atoms are balanced by adding 2 H+ atoms on the LHS.

3AsO33−+2MnO4−+2H+→3AsO43−+2MnO2+H