Question

Balance the following equation by
oxidation number or ion electron method.
K2Cr2O7 + SnCl2 + HCI- CrCl3 + SnCla+KCI + H2O​

Answer 1

Answer:

Explanation:

k2cr2o7+sncl2+hcl = cr(cl)3  + sncl4 + kcl

when balancing any reaction water should be removed

now find valency factor of cr in crcl3 = 4

valency factor of sncl4 in sncl2 =2

now interchange karo valency factor

k2cr2o7 + sncl2 + hcl = 2crcl3+4sncl4 + kcl

now balance others

k2cr2o7 + 4sncl2 + 16hcl +14hplus + 14 e= 2crcl3+4sncl4 + 2kcl + 7h2o