Question

balance the following equation
Ca(OH)2 + HCI = CaCI2 + HO

Answer 1

Answer:

Ca(OH)2+2HCl = CaCl2+2OH

Explanation:

Ca= 2. Ca= 2

HO = 2. OH=2

Cl= 2. Cl= 2

Equation balanced

Answer 2

Answer:

$\sf Ca(OH)_2(aq) + 2HCl(aq) \longrightarrow CaCl_2(aq) + 2H_2O(l)$

Explanation:

Steps to balance an equation:

Step 1

Count the number of atoms of each elements.

$\boxed{\begin{array}{c|c|c} Atoms & Number \ in\ LHS & Number \ in \ RHS \\ \hline \\ Ca & 1 & 1 \\ O & 2 & 1 \\ H & 3 & 2 \\ Cl & 1 & 2\end{array}}$

Step 2

Now make the atoms equal by multippying with coefficients. Firstly balancing O is preffered here. Equation becomes :

$\sf Ca(OH)_2(aq) +HCl(aq) \longrightarrow CaCl_2(aq) + \red2H_2O(l)$

This is a partially balanced equation. And now we have

$\boxed{\begin{array}{c|c|c} Atoms & Number \ in\ LHS & Number \ in \ RHS \\ \hline \\ Ca & 1& 1 \\ O &2&2\\ H&3&4\\ Cl &1&2\end{array}}$

Step 3

Now we will balance H. For that we have to multiply HCl with 2 in RHS. Equation becomes:

$\sf Ca(OH)_2(aq) + \red2HCl(aq) \longrightarrow CaCl_2(aq) + 2H_2O(l)$

This is a completely balanced equation and now we have:

$\boxed{\begin{array}{c|c|c} Atoms & Number \ in\ LHS & Number \ in \ RHS \\ \hline \\ Ca & 1& 1 \\ O &2&2\\ H&4&4 \\ Cl &2&2\end{array}}$

Thus , your completely balanced equation becomes,

$\boxed{\boxed{\sf Ca(OH)_2(aq) + 2HCl(aq) \longrightarrow CaCl_2(aq) + 2H_2O(l)}}$

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