Question

Balance the following equation
H 2 s 2 O 7 (1)+H 2 O(1) H 2 SO 4 (1)​

Answer 1

Answer:

H₂S2O7(1) + H₂O(1)→ H₂SO4(1)

Step 1. Count the number of each atom

in reactant side:

H= 4

S=2

0=8

Step2. Count the number of each atom

in product side:

H=2

S=1

0=4

Step3.Then balance the number of each

atom in an equation by multiplying

reactant and product side with numeral

value:

If we multiply product side by 2, then

number of atoms in product and

reactant side gets balance.

H₂S₂07(1) + H₂O(1)→ 2H₂SO4(1)

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Answer 2

Explanation:

Explanation:

⇒ Step 1: Write the given unbalance equation

H2S2O7 + H2O(l)

H2SO4(l)

⇒ Step 2: Compare the number of atoms of reactants with the number of atoms of products.

⇒ Step 3: Now, if we multiply 2 in the products, we will get the equal number of atoms as reactants.

⇒ Write down the final balanced equation:

H2S2O7 + H2O → 2H2SO4