Balance the following equation : (I) Na2O2 + H2O ----- NaOH + O2 (ii) CI2 + NaOH ------ NaCI + NaCIO3 + H2O (iii) Cu + HNO3 ----- Cu(NO3)2 in 2 marks
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2Na2O2 + 2H2O → 4NaOH + O2
6NaOH + 3Cl2 → 5NaCl + NaClO3 + 3H2O
3Cu+8HNO3⟶3Cu(NO3)2+2NO+4H2O
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Answer:
2Na202 + 2H2O → 4NaOH + O2
6NaOH + 3C12 → 5NaCl + NaCIO3 + 3H2O
3Cu+8HNO3-3Cu(NO3)2+2NO+4H20
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