Balance the following equation in acidic medium Cr2O7 + Mn ----> Mn + Cr
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Cr2O72- + 2 H+ + 3 (Mn)2+ → 2 (Cr)3+ + 3 MnO2 + H2O
This is an oxidation-reduction (redox) reaction:
3 MnII - 6 e- → 3 MnIV
(oxidation)
2 CrVI + 6 e- → 2 CrIII
(reduction)
Mn2+ is a reducing agent, Cr2O72- is an oxidizing agent.
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