Balance the following equation :MnO4- + I- --> MnO2 + IO3- (basic medium) in half reaction method not oxidation.
Answers
Answered by
1
Answer:
3MnO4 + 2I → 3MnO2 + 2IO3
Answered by
0
Answer:2 MnO⁴⁻ + I⁻ + H₂O ====== > 2 MnO₂ + IO³⁻ + 2 OH⁻
Explanation:
The given equation is :
MnO⁴⁻ + I⁻ ====== > MnO₂ + IO³⁻
The complete equation will be :
MnO⁴⁻ + I⁻ + H₂O ====== > MnO₂ + IO³⁻ + OH⁻
In order to balance the equation proceed these steps :
Add 2 beside MnO⁴⁻ .
Add 2 beside MnO₂ so as to balance the Mn .
Add 2 beside OH⁻ .
Count and see whether they are balanced or not .
Mn = 2
O = 8 + 1 = 9
I = 1
H = 2
This is balanced on both sides .
BALANCED EQUATION :
2 MnO⁴⁻ + I⁻ + H₂O ====== > 2 MnO₂ + IO³⁻ + 2 OH⁻
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